There's a baseball equation that kind of looks like that and so it uses that name.
pythagorean winning percentage:
(Runs Scored)^1.83 + (Runs Allowed)^1.83
The traditional formula uses an exponent of two, but this has proven to be a little more accurate.
I compared actual regular season wins with the number estimated by Pythagorean winning percentage.
|team||Wins||Pyth||W-P||WC||series 1||series 2|
|Baltimore Orioles||96||94||2||Bal beat Det 3-0|
|Kansas City Royals||89||84||5||KC beat Oak||KC beat Ang 3-0||KC beat Bal 4-0|
|Los Angeles Dodgers||94||92||2|
|St. Louis Cardinals||90||83||7||StL beat LA 3-1|
|San Francisco Giants||88||87||1||SF beat Pit||SF beat Was 3-1||SF beat StL 4-1|
If the difference is truly luck, then Kansas City was lucky to have qualified for the tournament at all as it projected to only 84 Pyth wins. In the wild card game Kansas City was MINUS 15 Pyth wins to a very unlucky Oakland team. That was the first of multiple extra inning games that KC won in the tournament. Even with its 8-0 record in the tournament, KC still has fewer wins than the Angels.
Baltimore was plus 8 Pyth wins over Detroit, which it swept, and plus 10 Pyth wins over KC, which swept Baltimore.
San Francisco was even with Pittsburgh, except that the Pirates had home field in their wild card game. Washington was plus 10 Pyth wins over SF but still lost.
SF was plus four Pyth wins over St Louis, so SF winning was not really much of an upset, especially with StL literally throwing away two games.
So in addition to the obvious stuff so far in this loony tournament suggesting that Lady Luck is involved, Pythagoras weighs in to confirm our suspicions.